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1.What is the **minimum number** of binary **bits** needed to **represent** each of the following decimal **numbers**? Please write your answers in **number** format such as 6 or 8. Do NOT write five or "it. Integer Min and Max ¶ The int type in Java can be used to represent any whole number from -2147483648 to 2147483647. Why those numbers? Integers in Java are represented in 2’s complement binary and each integer gets 32 bits of space. In 32 bits of space with one bit used to represent the sign you can represent that many values. **minimum** value of n is 8. For signed form: - (2 n-1 - 1) ≤ -128. 2 n-1 ≥ 128 + 1 ≥ 129. n ≥ 9. Therefore the **minimum number of bits required to represent -128** 10 in 2's complement form and signed form respectively are. What is the **minimum number of bits** necessary **to represent** these states? Answer. Upgrade to View Answer. Related Courses. No Related Courses. Digital Design and Computer Architecture. Chapter 3. Sequential Logic Design. Related Topics. No Related Subtopics. Discussion. You must be signed in to discuss. Top Educators. Recommended Videos. Watch More Solved Questions. Minimum number of bits required in sequence number field = 7 With 7 bits, number of sequence numbers possible = 128 We use only (1+2a) = 109 sequence numbers and rest remains unused. Problem-02: Compute approximate optimal window size when packet size is 53 bytes, RTT is 60 msec and bottleneck bandwidth is 155 Mbps. Solution- Given-. 1.8 binary storage & registers 79 a binary cell is a device that possesses two stable states and is capable of storing one **bit** (0 or 1) of information. aregister is a group of binary cells. an n-bit register can store a binary **number** from 0 to 2n 1. the information stored in any register may be interpreted differently for different types of. **Bit** rate. **Bit** rate indicates the amount of information transferred on a channel, and is measured in **bits** per second or bps. **Bit** rate is different from baud if more than one **bit** is transferred per symbol. For example, in a 4-level amplitude modulation scheme, each symbol can encode 2 **bits** **of** information. **Minimum** **number** **of** **bits** required to **represent** $(+32)_{base10}$ and $(-32)_{base10}$ in signed two's compliment form? Click to expand... My attempt: $32 = 0100000$ (1st **bit** $0$ - sign **bit** **as** positive) So to **represent** $+32$ we need $7$ **bits**. -32 = 1100000 (1st **bit** $1$ - sign **bit** **as** negative) So to **represent** $-32$ we need $7$ **bits**. Use the **minimum number of bits**. Hint: Use a six-**bit** code. Use the first two **bits** to encode the suits, and the rest to encode different cards in each suit. For instance, use 00, 01, 10, 11, **to represent** spate, heart, diamond, and club; use 0001, 0010, 0011, ..., 1011, 1100, 1101 **to represent** Ace, 2, 3, ..., Jack, Queen, and King, respectively, in each suit. 1-26 List the ten BCD digits with. We will then simply adhere to this implicit convention when we **represent numbers**. To define a **fixed point** type conceptually, all we need are two parameters: width of the **number** representation, and; binary point position within the **number**; We will use the notation fixed<w,b> for the rest of this article, where w denotes the **number of bits** used as a whole (the Width of **a**. Convert the following **numbers** from Base 2 to base 10. For full credit, show some of your work for each **number**. 10011 2: convert to base 10 ; 111011 2: convert to base 10 ; 00110 2: convert to base 10 ; This tutorial gives you several ways of converting decimal **numbers** to binary. I tend to favor the first method which involves repeatedly dividing by two and keeping track of. On Marx and Labor Certificates Conrad Hamilton October 10, 2022 Flirting with the Future For a man widely regarded as the founder of "scientific socialism," Karl Marx did not, in fact, write very much about it. It is true, of course, that all of his writings dwell upon socialism, in the sense of treating it as a terminus that the Victorian capitalism of the nineteenth century was rapidly. What is the **minimum number of bits** required **to represent** at least 7different values 2 See answers Advertisement Advertisement rabeehmattath1998 rabeehmattath1998 Answer: HELLO, Explanation: 16, which is 2^4. Therefore, we need at least 4 **bits to represent** 11 values. Advertisement Advertisement maveron1334 maveron1334 Answer: 8bits. Explanation: bcos u. **Minimum number** of **bits** required for each character. Ask Question Asked 8 years, 5 months ago. Modified 8 years, 5 months ago. Viewed 1k times 0 $\begingroup$ Assuming that. With code 2, **number of bits** needed **to represent** the entire image MNL avg = 256 256 1:81 = 118;621bits Compression ratio C= 256 256 8 256 256 1:81 ˇ4:42 Redundancy R= 1 1 4:42 = 0:774 Compression comes from assigniong fewer **bits** to the code for more probable intensity values l 2(r 128) = 1 l 2(r 255) = 3 In the best ﬁxed-length code, we have the natural 2-**bit** counting. **To** ensure resiliency, a **minimum** **of** three separate availability zones are present in all availability zone-enabled regions. Azure availability zones are connected by a high-performance network with a round-trip latency of less than 2ms. They help your data stay synchronized and accessible when things go wrong. Each zone is composed of one or. How many bits does a 1000 digit number need? For the decimal number system R=9 so we solve 9=2^n, the answer is 3.17 bits per decimal digit. Thus a 3 digit number will need. Minimum number of bits required in sequence number field = 7 With 7 bits, number of sequence numbers possible = 128 We use only (1+2a) = 109 sequence numbers and rest remains unused. Problem-02: Compute approximate optimal window size when packet size is 53 bytes, RTT is 60 msec and bottleneck bandwidth is 155 Mbps. Solution- Given-. 512 happens to be or or . Since 512 is equal to , N is equal to 9. Thus, the **number of bits** required **to represent** 512 unique integer values is 9. The values range in binary from 000000000 through 111111111, or 0 through 511 in decimal. What is the **minimum** **number** **of** **bits** needed to **represent** **a** **number** on a 0 to 10 scale? 10 = 3.32 **bits** are needed on the average to encode a digit. In computers **numbers** are stored as a sequence of 8-bit bytes. Thus 32 **bits** (4 bytes) which is bigger than 26 **bits** is a logical size to use for real **numbers**. The smallest number that can be represented using 8 bits is 00000000 – which is 0. And the largest number that can be represented using 8 bits is 11111111 – which is 255. Because there are three primary colours, each of which will need 8 bits to represent each of its 256 different possible values, we need 24 bits in total to represent a colour. Four modes of rounding IEEE 754-1985 defines four format for floating-point numbers: Single-precision (single-precision) 32-bit Double-precision (double-precision) 64-bit With single extended precision (single-extended precision)> = 43 bits (seldom used) Double-extended precision (double-extended precision)> = 79 bits (typically use 80 bit) §3. What is the **minimum number** of **bits** required to **represent** the addresses only for this memory device? Categories: Engineering. Search for: Recent Posts. IRR and Accept or. How many **bits** does a 1000 digit **number** need? For the decimal **number** system R=9 so we solve 9=2^n, the answer is 3.17 **bits** per decimal digit. Thus a 3 digit **number** will need 9.51 **bits** or 10. A 1000 digit **number** needs 3170 **bits** Which is the maximum decimal value you can hold?. Answer: N >/= 7 **bits**. **Minimum** **of** 7 **bits**. Step-by-step explanation: The **minimum** binary **bits** needed to **represent** 65 can be derived by converting 65 to binary **numbers** and counting the **number** **of** binary digits. See conversation in the attachment. 65 = 1000001₂. 65 = 7 **bits** :( 0 to 2^7 -1) The **number** **of** binary digits is 7. N >/= 7 **bits**. Something I've been working on for a **bit**. PDF Teaching Strategies Mighty Minutes for Preschool. The 8 Minute Rule - How Does It Work? Page 4 The 8 Minute Rule - How Does It Work? 8 Minute Rule Table Below is the 8 Minute Rule table to help you determine the total **number** **of** minutes service was provided and the total **number** **of** units you can bill for. So back to answer our initial question of the minimum subnet size to accommodate 20 hosts, the minimum number of host bits required is 5 bits (2^5 = 32). 4 bits (2^4 = 16) will be too small. So 5 bits used for the host IDs leaves us with 32 – 5 = 27 network bits. Therefore, the minimum subnet size we can use is /27. Let’s try another one. Engineering. Computer Science. Computer Science questions and answers. What is the **minimum number of bits** required **to represent** at least 8 different values? Please enter only a numeric value Answer: What is the **minimum number of bits** required **to represent** at least 16 different values? Please enter only a numeric value Answer:. As u can see we have used total** 6** right shift operation ( >> ) to get 0, so** 6** will be required number of minimum bits to represent a number in binary. Program: # include <. 2.1.1C At a higher level, **bits** are grouped **to represent** abstractions, including but not limited to **numbers**, characters, and color. 2.1.1D **Number** bases, including binary, decimal, and hexadecimal, are used **to represent** and investigate digital data. 2.1.1E At one of the lowest levels of abstraction, digital data is represented in binary (base 2) using only combinations of the. . Required **bits** to **Represent** a **Number** - Part B. 40,976 views. Jan 25, 2018. 293 Dislike Share Save. Tutorials Point (India) Ltd. 2.81M subscribers. The network portion is like the city, state, and zip code. The host portion is like the house and street **number**. A subnet defines the **number of bits**, out of 32, used for the “network portion” of the address. Subnet masks can also be defined in a more common ‘slash’ representation, known as CIDR notation. What is the **minimum** **number** **of** **bits** required to **represent** at least 15 different values ? 03:21. 3) What is the largest binary **number** that can be expressed with 16 **bits**? What are the equivalent decimal and hexadecimal **numbers**? Additional Computer Science questions. 02:00. 32 = 0100000 ( 1st zero - sign **bit** **as** positive) So to **represent** +32 we need 7 **bits** -32 = 1100000 (1st **bit** 1 - sign **bit** **as** negative) So to **represent** -32 we need 7 **bits** But answer is given as 6 **bits** **to** store -32 and 7 **bits** **to** store +32 (positve case i understood, negative in my opinion it should be 7 **bits**). There are just two options: 0 or 1. A 2-**bit** system uses combinations of **numbers** up to two place values (11). There are four options: 00, 01, 10 and 11. A 1-**bit** image can have 2 colours, a 4-**bit**. Engineering. Computer Science. Computer Science questions and answers. What is the **minimum number of bits** required **to represent** at least 8 different values? Please enter only a numeric value Answer: What is the **minimum number of bits** required **to represent** at least 16 different values? Please enter only a numeric value Answer:. We will then simply adhere to this implicit convention when we **represent numbers**. To define a **fixed point** type conceptually, all we need are two parameters: width of the **number** representation, and; binary point position within the **number**; We will use the notation fixed<w,b> for the rest of this article, where w denotes the **number of bits** used as a whole (the Width of **a**. Output: $ go run sample.go **minimum** **number** **of** **bits** required to **represent** **number**: 5 ==>> **number** = 16, in **bits**: 10000 i.e 5 **bits** **minimum** **number** **of** **bits** required to **represent** **number**: 6 ==>> **number** = 32, in **bits**: 100000 i.e 6 **bits** **minimum** **number** **of** **bits** required to **represent** **number**: 7 ==>> **number** = 64, in **bits**: 1000000 i.e 7 **bits** **minimum** **number** **of**. The date was chosen **to represent** the day United Nations Radio was launched in 1946. World Radio Day provides an annual opportunity to celebrate radio and how it fosters public debate through information, entertainment and dialogue with audiences. UNESCO is seeking for a company to produce campaign material that will recognize and mark World Radio Day by. Related The **minimum number** of **bits** required to **represent** - 64 in 2’s complement representation is _____.Correct answer is '7'. Can you explain this answer? Whenever a **number** is in 2 n form. Step by step descriptive logic to get nth **bit** of **a number**. Input **number** from user. Store it in some variable say num. Input the **bit** position from user. Store it in some variable say n. To get the nth **bit** of num right shift num, n times. Then perform bitwise AND with 1 i.e. bitStatus = (num >> n) & 1;. We have used 6 **bits** **to** **represent** 48 in binary. What is the **minimum** **number** **of** **bits** required to **represent** **to** 31? 5 **bits** 011111 = 31, so 5 **bits**, are absolutely necessary for representing the **number** 31. A hexadecimal digit needs 4 binary digits. Therefore 4 k binary digits are required to **represent** k hexadecimal digits. Calc **number** **of** **bits** needed to **represent** **a** value using TMP, IEEE Standard 754 Floating Point **Numbers**, What is the least **number** **of** bytes for representing date and time?, Given a matrix and some rules, what is the **minimum** **number** **of** days required to set all the **bits** **of** **a** binary matrix. Maximum value that can be represented: 2 N-1 (N is the **number of bits**) PROS. The **bits** in the pattern determine the value represented according to the normal positional **number** system rules. CONS. Can not **represent** negative **numbers**. Signed Binary. **Minimum** value that can be represented: -(2 N-1) (N is the **number of bits**). Question 3: What is the maximum **number of bits** needed **to represent** 15 in denary? (3-5) ... Question 7: Question 7: What is the Denary representation of this 8 **bit number**? 11010101 (5-7) ü 199 206 228 213 ü MCQS ANSWERS Unit 2.6 Data Representation Lesson 1 - **Numbers**. 4 2016 GCSE 9˚1 COMPUTR CIENCE MC n nswers OCR Resources: the small print OCR’s resources are. With 3 flip-flops, there are 3 state bits, for 2 3 = 8 states. Technically, 8 is both the minimum and maximum; you always have 8 states. It is simply the case that there will sometimes be invalid or dead states the you will never enter. I accepted a minimum value of 1 as correct. Number of transitions arrows leaving a state. With 11 bits allocated to the exponent, this makes 2048 values that this number can take. Since we want to be able to make very precise numbers, we want some of these values to represent negative exponents (i.e., to allow numbers that are between 0 and 1 (base10)). To accomplish this, 1023 is subtracted from the exponent to normalize it. **Minimum** **number** **of** **bits** required for each character. Ask Question Asked 8 years, 5 months ago. Modified 8 ... interfaced with a device that has 210 characters and that each character is transmitted using binary words what is the **minimum** **number** **of** **bits** needed to **represent** each character? To find the **minimum** is there any specific formula ?. Then we can see that it is very easy to find the one’s complement of a binary **number** N as all we need do is simply change the 1’s to 0’s and the 0’s to 1’s to give us a -N equivalent. Also just like. A 10-bit binary number cannot exceed: 11 1111 1111 or 3FF h or 1023 decimal. But, the maximum number of Cylinders we can reference in 10 bits is 1024, since we begin counting from zero. **Normalised Floating point**. We want the floating point system **to represent** as wide a range of real **numbers** with as much precision as possible. Don't forget, only a fixed **number of bits** are available in any given scheme (8 **bit**, 16 **bit**, 32 **bit**, 64 **bit** and so on). For example, say you want to use an 8 **bit** scheme. Say, 3 **bits** for the exponent, 1 **bit**. What is the **minimum number** of **bits** required to **represent**: 341,000 symbols? Symbols that **represent numbers** between 25,000 and 33, 192? A microprocessor has a memory space of 4. Upload Solutions of any coding Platform. In designated folder if not there make new folder and upload. - Data-Structure-Algorithms-open-source/**Minimum Bit** Flips to Convert **Number** at master · umangb. The maximum **number** **of** **bits** sufficient to **represent** **a** hexadecimal **number** in binary: (**a**) 4 (b) 3 (c) 7 (d) 8 computer-fundamentals **number**-systems 1 Answer 0 votes answered Feb 20 by PritamBarman (89.0k points) selected Mar 11 by Rupsakundu Best answer Correct choice is (**a**) 4. The maximum **number** **of** **bits** sufficient to **represent** **a** hexadecimal **number** in binary: (**a**) 4 (b) 3 (c) 7 (d) 8 computer-fundamentals **number**-systems 1 Answer 0 votes answered Feb 20 by PritamBarman (89.0k points) selected Mar 11 by Rupsakundu Best answer Correct choice is (**a**) 4. 32 = 0100000 ( 1st zero - sign **bit** **as** positive) So to **represent** +32 we need 7 **bits** -32 = 1100000 (1st **bit** 1 - sign **bit** **as** negative) So to **represent** -32 we need 7 **bits** But answer is given as 6 **bits** **to** store -32 and 7 **bits** **to** store +32 (positve case i understood, negative in my opinion it should be 7 **bits**). **A** 32-**bit** system can access 2 32 different memory addresses, i. Intuit®: Complete Financial Confidence. **Minimum** Qualifications:Associate's Degree in an information systems related field (e. ... This presentation file includes facts, each demographic groups. This **number** **represents** the median, which is the midpoint of the ranges from our. I'm going to scroll up, just gonna scroll up just a little **bit**, do that just a little **bit**. That gives me a little **bit** more space here. ... (1.08)^{t} \) at \( t=10 \). 13. State two types of functions that you know that do not have a maximum or a **minimum** (unless the domain is restricted to some interval). ... for each increase of $\$ 20$ in. c. What is the maximum **number** of UNUSED **bits** in the encoding? Solution: a. **Minimum number of bits** for opcodes: 8 (225 lies between 2 7 = 128 and 2 8 = 256) b. **Minimum number of bits** required for Destination Reg: 7 (120 lies between 26 = 64 and 2 7 = 128) c. Maximum **number** of UNUSED **bits** in the encoding: 32 - 8 - 7 – 7 - 7 = 32 - 29 = 3 (total. By looking at the way floating point **numbers** are stored, it’s possible to understand why this happens and what precision is likely to be available. Hypothetically, it’s possible under certain circumstances to get up to about 45 decimal places in a C++ float, and 324 in a double. However, as we’ll see in this post, it depends on context. Signed integers use half of the possible **bit** patterns **to represent** negative **numbers**, one pattern **to represent** zero, and half minus 1 **to represent** positive values. Specific details of the integer types available on a particular implementation, along with the **number of bits** allocated to each one and their **minimum** and maximum allowable values can be found in the file limits.h; int .. A **bitmap** is an array **of bits** that specifies the color of each pixel in a rectangular array of pixels. The **number of bits** devoted to an individual pixel determines the **number** of colors that can be assigned to that pixel. For example, if each pixel is represented by 4 **bits**, then a given pixel can be assigned one of 16 different colors (2^4 = 16). In digital computer, 1's complement and 2's complement **is used to represent negative numbers**.. 1's complement:- The ones' complement of a binary **number** is defined as the value obtained by inverting all the **bits** in the binary representation of the **number**. The ones' complement of the **number** then behaves like the negative of the original **number** in some arithmetic operations. Create a binary representation with it's 'n' least significant **bits** set to 1. 4. Convert the binary representation back to the **number**. Efficient Approach: 1. Just measure the **number** **of** 1's present in the **bit** representation of the **number**. 2. (**Number** **of** set **bits** raised to the power of 2) - 1 **represents** the minimized **number**. C++ Java Python3 C#. <strong>We're sorry but **bit**-calculator doesn't work properly without JavaScript enabled. Please enable it to continue.</strong>. Required **bits** to **Represent** a **Number** - Part B. 40,976 views. Jan 25, 2018. 293 Dislike Share Save. Tutorials Point (India) Ltd. 2.81M subscribers. 1.What is the **minimum number** of binary **bits** needed to **represent** each of the following decimal **numbers**? Please write your answers in **number** format such as 6 or 8. Do NOT write five or "it. The smallest **number of bits** that the computer can use is 8 **bits**. With 8 **bits**, we can values between [-2 7, 2 7-1] = [-128, 127] The ... The computer can use different **numbers of bits to represent** integer quantities: byte (very short integer, values between -127 and 128). 512 happens to be or or . Since 512 is equal to , N is equal to 9. Thus, the **number of bits** required **to represent** 512 unique integer values is 9. The values range in binary from 000000000 through 111111111, or 0 through 511 in decimal. It's in for night physicals toe a divide by one minus are so it is one before minus one minus one by our here is it is also one by four. So you get the result US one divide by three. So finally we can conclude that the bind remember which was 0.10101 On distributing like this is it cools to one divide by three. This is the final. Here's a way to think about it. A single **bit** can hold two values. If you add another **bit**, that means that there are now twice as many possibilities. We can say that in math. If there are two **bits**, the possibilities are 2*2. If there are 3 **bits**, the possibilities are 2*2*2. Said another way, the **number** **of** possibilities is 2 n. Upload Solutions of any coding Platform. In designated folder if not there make new folder and upload. - Data-Structure-Algorithms-open-source/**Minimum Bit** Flips to Convert **Number** at master · umangb. **A** 32-**bit** system can access 2 32 different memory addresses, i. Intuit®: Complete Financial Confidence. **Minimum** Qualifications:Associate's Degree in an information systems related field (e. ... This presentation file includes facts, each demographic groups. This **number** **represents** the median, which is the midpoint of the ranges from our. **Network Bits** and Host **Bits** from Wildcard Mask 0.0.0.127. Write Wildcard Mask in binary WM = 00000000.00000000.00000000.01111111 Now simply count **number** of '0' and **number** of '1' for **Network Bits** and Host **Bits** respectively. This article throws light upon the four **main types of number system**. The types are: 1. Decimal System 2. Binary System 3. The Octal System 4. The Hexadecimal System. Type # 1. Decimal System: In decimal system the base (or radix) is 10, since any position can contain one of ten digits, refer (3) above. Related The **minimum number** of **bits** required to **represent** - 64 in 2’s complement representation is _____.Correct answer is '7'. Can you explain this answer? Whenever a **number** is in 2 n form. Answer: N >/= 7 **bits**. **Minimum** of 7 **bits**. Step-by-step explanation: The **minimum** binary **bits** needed to **represent** 65 can be derived by converting 65 to binary **numbers** and. 4 **bits** equal to half byte.8 **bits** is one byte.when converting hexadecimal digits to binary, each hexadecimal digits will take 4 binary digits, which means 4 **bits**.Because one binary digit means one **bit** having two values [true/false] or [on/off] like that.. [0/1]we can **represent** one hexadecimal digit as 4 **bits** like..for [7] as hexadecimal, we can say [0111] in **bits**. The ranges and quantity of integers that can be represented with 9 bits vary depending on the system utilized. F.A.Q: The minimum number of bits required to represent 9 unique states are.. This means that binary digit (or "**bit**") only has two states: 1 and 0. As a result, binary **numbers** are well suited for electronic circuits since they can be represented as ON or OFF states, and they're therefore used as the fundamental data format in computers. A collection of 8 **bits** is commonly referred to as Byte. There are 2 8 different combinations **of bits** in a byte, and it can therefore. absolute **minimum** amount of storage and transmission needed for succinctly capturing any information (as opposed to raw data), and in typical cases that amount is less than what is required to store or transmit the raw data behind the information. Shannon’s Entropy metric also suggests a way of representing the information in the calculated fewer **number of bits**. The. If the company's engineers wanted to assign a unique **bit** pattern to each tower, what is the **minimum number of bits** they will need **to represent** all 701 towers 10 Is the following **number** positive or negative (assuming it has been represented using the two's complement convention in 7. Expert Answer. a) What is the **minimum number of bits** required **to represent**: ( 2 pts.) Memory addresses from 0 to 8192 ? 32767 symbols? b) A microprocessor has a 28-**bit** address line. The size of the memory contents of each address is 8 **bits**. The memory space is defined as the collection of memory positions the processor can address. ( 6 pts.). It typically has a size of 4 bytes (32 bits). Bits to represent the frame number. Bits for controlling virtual memory. With 32 bit physical addresses and 4KB pages the frame number only requires 20 bits. Then a 4B page table entry has 12 bits that can be used for controlling virtual memory. 2.81M subscribers. Required **bits** to **Represent** a **Number** - Part A Watch more videos at https://www.tutorialspoint.com/videot... Lecture By: Ms. Gowthami Swarna, Tutorials Point. First, you have to add 2 addresses to the **number** of hosts you want. These are for network and broadcast addreses (therefore, for 20 hosts you get 20+2=22) Now, count **how many bits** you used and that's your answer (in this case, it will be 5 **bits**, so 32-5=27 **bits** for network) Your subnets will be then 200.35.1.0/27, 200.35.1.32/27, 200.35.1.64/27. c. What is the maximum **number** of UNUSED **bits** in the encoding? Solution: a. **Minimum number of bits** for opcodes: 8 (225 lies between 2 7 = 128 and 2 8 = 256) b. **Minimum number of bits** required for Destination Reg: 7 (120 lies between 26 = 64 and 2 7 = 128) c. Maximum **number** of UNUSED **bits** in the encoding: 32 - 8 - 7 – 7 - 7 = 32 - 29 = 3 (total. How many bits does a 1000 digit number need? For the decimal number system R=9 so we solve 9=2^n, the answer is 3.17 bits per decimal digit. Thus a 3 digit number will need. mantissa sizes to accurately mirror the C standard **minimum** widths. Not sure my log calcs are correct..... AFAIK the sizes for real **numbers** must be at least float: range 10^+/-37, precision 6 digits double: range 10^+/-37, precision 10 digits I think this means the **number of bits** used would be float: 8 **bits** for exponent, 20 **bits** for mantissa. Create a binary representation with it’s ‘n’ least significant bits set to 1. 4. Convert the binary representation back to the number. Efficient Approach:. Shifts this value right by the bitCount **number of bits**, ... A constant holding the **minimum** value an instance of **Int** can have. const val MIN_VALUE: **Int**. Common. JVM. JS. Native. 1.3. SIZE_**BITS** . The **number of bits** used **to represent** an instance of **Int** in a binary form. const val SIZE_**BITS**: **Int**. Common. JVM. JS. Native. 1.3. SIZE_BYTES. The **number** of bytes used **to**. 6. What is the **minimum number** of binary **bits** needed **to represent** each of the following unsigned decimal integers? a. 4095 - 4 b. 65534 - 3 C. 42319 3 Show transcribed image text 6. 5. What is the **minimum number of bits** required **to represent** each of the following decimal **numbers**: 10, 1000, 100,000, and 1,000,000? 6. Convert the binary value 1011010100101101 to a hexadecimal equivalent. 7. Convert the following decimal **numbers** to 8-**bit** binary values. For negative **numbers**, use the 2%u2019complement formulation. a. -78b. -37c. How many **bits** does a 1000 digit **number** need? For the decimal **number** system R=9 so we solve 9=2^n, the answer is 3.17 **bits** per decimal digit. Thus a 3 digit **number** will need 9.51 **bits** or 10. A 1000 digit **number** needs 3170 **bits** Which is the maximum decimal value you can hold?.

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- In Number System we’ve assumed, we have as many bits as needed to represent numbers. But in computers, we have a fix number of bits to represent value. These bit sizes are typically 8-bit, 16-bit, 32-bit, 64-bit. These sizes are usually multiple of 8, because system memories are organized on an 8-bit byte basis.
- mantissa sizes to accurately mirror the C standard
**minimum**widths. Not sure my log calcs are correct..... AFAIK the sizes for real**numbers**must be at least float: range 10^+/-37, precision 6 digits double: range 10^+/-37, precision 10 digits I think this means the**number of bits**used would be float: 8**bits**for exponent, 20**bits**for mantissa - In either case, the standard deviation, as a percentage of the full signal range, changes by a factor of 2 for each 1-
**bit**change in the**number**of quantization**bits**. The potential signal-to-quantization-noise power ratio therefore changes by 4, or 10 ⋅ log 10 ( 4 ) {\displaystyle \scriptstyle 10\cdot \log _{10}(4)} , approximately 6 dB per**bit**. - I'm going to scroll up, just gonna scroll up just a little
**bit**, do that just a little**bit**. That gives me a little**bit**more space here. ... (1.08)^{t} \) at \( t=10 \). 13. State two types of functions that you know that do not have a maximum or a**minimum**(unless the domain is restricted to some interval). ... for each increase of $\$ 20$ in ... - This means that binary digit (or "
**bit**") only has two states: 1 and 0. As a result, binary**numbers**are well suited for electronic circuits since they can be represented as ON or OFF states, and they're therefore used as the fundamental data format in computers. A collection of 8**bits**is commonly referred to as Byte. There are 2 8 different combinations**of bits**in a byte, and it can therefore